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12e^2-17e+6=0
a = 12; b = -17; c = +6;
Δ = b2-4ac
Δ = -172-4·12·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-1}{2*12}=\frac{16}{24} =2/3 $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+1}{2*12}=\frac{18}{24} =3/4 $
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